Question 12601: How many gallons of pure antifreeze must be added to 20 gallons of 25% antifreeze to get a mixture that is 40% antifreeze Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! Let x = amt of pure antifreeze to be added
You are adding this to 20 gallons of 25% and you will end up a total mixture of x+ 20 at 40%.
The equation is
.25(20) + x = .40(x+20)
5 + 1.00x = .40x + 8
1.00x - .40x = 8 - 5
.60x = 3
Does it check?? (It is VERY late in Florida, here! I don't guarantee my work or my spelling at this hour!!}}}
