SOLUTION: This is the question: A chemist wants to mix 46% and 56% alcohol solutions to make 40 liters of 47% alcohol solution. How many liters of 46% alcohol solution is necessary?(Please H

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: This is the question: A chemist wants to mix 46% and 56% alcohol solutions to make 40 liters of 47% alcohol solution. How many liters of 46% alcohol solution is necessary?(Please H      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 12568: This is the question: A chemist wants to mix 46% and 56% alcohol solutions to make 40 liters of 47% alcohol solution. How many liters of 46% alcohol solution is necessary?(Please Help)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You can write the equation as follow: Change percent to decimals: 46% = 0.46, 56% = 0.56, 47% = 0.47 Let x = the number of liters 46% alcohol solution.
x%280.46%29+%2B+%2840-x%29%280.56%29+=+40%280.47%29
0.46x+%2B+22.4+-+0.56x+=+18.8 Solve for x.
-0.1x+%2B+22.4+=+18.8
-0.1x+=+-+3.6
x+=+36
You would need 36 liters of 47% alcohol solution.