SOLUTION: What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 ml of a 55% solution? I have tried these equations .75x+.25(.55*500)=500(.55)

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Question 124264: What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 ml of a 55% solution?
I have tried these equations
.75x+.25(.55*500)=500(.55)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You are close, but since the final solution is 500 ml and the first quantity is x ml, then the second quantity is 500-x ml


So the equation should be

0.75x%2B.25%28500-x%29=500%28.55%29


0.75x%2B.25%28500-x%29=275 Multiply


0.75x%2B125-0.25x=275 Distribute


0.50x%2B125=275 Combine like terms


0.50x=150 Subtract 125 from both sides


x=300 Divide both sides by 0.50 to isolate x



So you need 300 ml of the 75% solution