SOLUTION: Twenty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to twelve percent salt?
Question 121986: Twenty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to twelve percent salt? Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! Salt= 20(0,15)=3 pounds, you must add x pounds of water where:
3/(20+x)=0,12 then 20+x=3/(0,12)=25 then x=5
You must add 5 pounds of water