SOLUTION: How much water should be added to 64 ounces of a 10% salt solution to make a 2% salt solution? Let me see. My equation is this one: (6.4)/(64 + x) = 0.02, where x r

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How much water should be added to 64 ounces of a 10% salt solution to make a 2% salt solution? Let me see. My equation is this one: (6.4)/(64 + x) = 0.02, where x r      Log On

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Question 1207793: How much water should be added to 64 ounces of a 10% salt solution to make a 2% salt solution?

Let me see.

My equation is this one:

(6.4)/(64 + x) = 0.02, where x represents the amount of water that needs to be added.

You say?


Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Study the solution in your previous post. Equation is shown there, arranged to account for the "percentages" as a rational expression.

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

Your setup equation is correct.

You may continue from this point to solve it and to find x.


There is another approach for solving this problem.

It is shown in my other post under this link

https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1207792.html


Happy learning !