SOLUTION: In the lab, Justin has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A as Solution B. Solution A is 16% alcohol and Soluti
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Question 1202257: In the lab, Justin has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A as Solution B. Solution A is 16% alcohol and Solution B is 11% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 177 milliliters of pure alcohol? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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In the lab, Justin has two solutions that contain alcohol and is mixing them with each other.
He uses 3 times as much Solution A as Solution B. Solution A is 16% alcohol and Solution B
is 11% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has
177 milliliters of pure alcohol?
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Let x be the volume of solution B in milliliters (the quantity under the problem's question).
Then the volume of the solution A is 3x milliliters, according to the problem.
Solution B contains 0.11x milliliters of the pure alcohol.
Solution A contains 0.16*(3x) milliliters of the pure alcohol.
Write equation for the total content of the pure alcohol
0.11x + 0.16*(3x) = 177 milliliter of the pure alcohol.
Simplify this equation and find x
0.11x + 0.48x = 177
0.59x = 177
x = 177/0.59 = 300.
ANSWER. Justin used 300 mL of solution B.