SOLUTION: A metallurgist has one alloy containing 28% titanium and another containing 45% titanium. How many pounds of each alloy must he use to make 43 pounds of a third alloy containing 31

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Question 1198483: A metallurgist has one alloy containing 28% titanium and another containing 45% titanium. How many pounds of each alloy must he use to make 43 pounds of a third alloy containing 31% titanium? (Round to two decimal places if necessary.)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Let x represent the amount of 45% alloy:
.45x + .28(43-x) = .31*43
x = .03*43/.17