SOLUTION: In the lab, Kevin has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A as Solution B. Solution A is 18% alcohol and Soluti
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Question 1196206: In the lab, Kevin has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A as Solution B. Solution A is 18% alcohol and Solution B is 11% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 390 milliliters of pure alcohol? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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In the lab, Kevin has two solutions that contain alcohol and is mixing them with each other.
He uses 3 times as much Solution A as Solution B.
Solution A is 18% alcohol and Solution B is 11% alcohol.
How many milliliters of Solution B does he use, if the resulting mixture has 390 milliliters
of pure alcohol?
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x mL of solution B and 3x mL of solution A.
0.11x mL of the pure alcohol goes with x mL of solution B,
and 0.18*(3x) mL of the pure alcohol goes with x mL of solution A.
Write an equation for the pure alcohol volume
0.11x + 0.18*(3x) = 390 mL
Simplify and find x
0.11x + 0.54x = 390
0.65x = 390
x = 390/0.65 = 600.
ANSWER. 600 mL of solution B should be used.
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