SOLUTION: A 30% antifreeze solution is to be mixed with a 90% antifreeze solution to get 18 liters of a 40% solution. How many liters of the 30% and how many liters of the 90% solutions will
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A 30% antifreeze solution is to be mixed with a 90% antifreeze solution to get 18 liters of a 40% solution. How many liters of the 30% and how many liters of the 90% solutions will
Log On
Question 1190855: A 30% antifreeze solution is to be mixed with a 90% antifreeze solution to get 18 liters of a 40% solution. How many liters of the 30% and how many liters of the 90% solutions will be used? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! .
A 30% antifreeze solution is to be mixed with a 90% antifreeze solution to get
18 liters of a 40% solution. How many liters
of the 30% and how many liters of the 90% solutions will be used?
~~~~~~~~~~~~~~~~~~~
Let x = the volume of the 90% solution to use, in liters.
Then the volume of the 30% solution is (18-x).
The basic equation is
0.90*x + 0.30*(18-x) = 0.4*28 (it is about the volume of the pure antifreeze)
From the equation
x = = 3 liters.
ANSWER. 3 liters of the 90% solution and (18-3) = 15 liters of the 30% solution.
Solved.
------------------
It is a standard and typical mixture word problem.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
A convenient place to quickly observe these lessons from a "bird flight height" (a top view) is the last lesson in the list.
Read them and become an expert in solution mixture word problems.
(