SOLUTION: Tom invests $7200 in two different accounts. The first account paid 6 %, the second account paid 12 % in interest. At the end of the first year he had earned $546 in interest. How

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Tom invests $7200 in two different accounts. The first account paid 6 %, the second account paid 12 % in interest. At the end of the first year he had earned $546 in interest. How       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1184987: Tom invests $7200 in two different accounts. The first account paid 6 %, the second account paid 12 % in interest. At the end of the first year he had earned $546 in interest. How much was in each account?
$ at 6 %
$ at 12 %

Answer by JBnovelwriter(34) About Me  (Show Source):
You can put this solution on YOUR website!
7200=a%2Bb

7200-a=b
0.06a%2B0.12b=546
0.06a%2B0.12%287200-a%29=546 multiply in
0.06a%2B864-0.12a=546 add the variables
-0.06a%2B864=546 subtract 864
-0.06a=-318 divide by -0.06
highlight%28a=5300%29 take this and put in first equation
7200=a%2Bb
7200=5300%2Bbsubtract 5300
highlight%281900=b%29