SOLUTION: Doris invested some money at 6% and some money at 7%. She invested $6,000 more at 7% than she did at 6%. Her total yearly interest from the two investments was $680. How much did D

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Doris invested some money at 6% and some money at 7%. She invested $6,000 more at 7% than she did at 6%. Her total yearly interest from the two investments was $680. How much did D      Log On

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Question 1184102: Doris invested some money at 6% and some money at 7%. She invested $6,000 more at 7% than she did at 6%. Her total yearly interest from the two investments was $680. How much did Doris invest at each rate?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


x = amount invested at 6%
x+6000 = amount invested at 7%

Total interest was $680:

.06%28x%29%2B.07%28x%2B6000%29=680

I personally would multiply by 100 to get rid of the decimals...

6x%2B7%28x%2B6000%29=68000

You can finish from there....

(final answers: $2000 at 6%, $8000 at 7%)