SOLUTION: needs a mix of a 10% solution with a 60% acid solution to create 200 milliliters of a 15% solution. how many milliliters of each solution must be use

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Question 1179764: needs a mix of a 10% solution with a 60% acid solution to create 200 milliliters of a 15% solution. how many milliliters of each solution must be use
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
.10(200-x) + .60x = .15*200
                x = .10*200/.50 = 40ml 60% solution 
                                 160ml 10% solution

 16 + 24 = 30 checks
Wish You the Best in your Studies.


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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a mix of a 10% solution with a 60% acid solution to create 200 milliliters of a 15% solution. how many milliliters of each ,...?
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L = 10 %
H = 60 %
T = 15%
-
M = 200
v, how much of the H concentration material

Hv%2BL%28M-v%29=MT
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Hv%2BML-Lv=MT
%28H-L%29v=MT-ML
highlight%28v=M%28%28T-L%29%2F%28H-L%29%29%29

Substitute the known values.
highlight_green%28v=200%28%2815-10%29%2F%2860-10%29%29%29
.
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