SOLUTION: You want to obtain a liter of a 12% salt solution, mixing X milliliters of an 8% salt solution with Y milliliters of another 18% salt solution, what will be the number of millilite
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Question 1163087: You want to obtain a liter of a 12% salt solution, mixing X milliliters of an 8% salt solution with Y milliliters of another 18% salt solution, what will be the number of milliliters in the new solution? (400 mL) Found 2 solutions by greenestamps, josgarithmetic:Answer by greenestamps(13200) (Show Source):
The question you ask is surely not the question you intended to ask. The number of milliliters in the new solution is 1000 -- that is given in the statement of the problem.
Obviously the intent of the problem is to find how many milliliters of each solution you need to mix to get the final 1000 ml of 12% salt solution.
You are mixing x ml of 8% salt solution with y ml of 18% salt solution to obtain 1 liter (1000 ml) of 12% salt solution. So you know
(1)
(2)
For an algebraic solution -- which you apparently need -- solve (1) for either x or y and substitute in (2), then solve the resulting equation.
I leave it to you to solve that equation to get the given answer.
Certainly you should understand how to set up a problem like this for solving using formal algebra.
However, if a formal algebraic solution is NOT required, there is a much faster and easier way to solve this kind of problem.
Look at where the target percentage of 12% lies between the 8% and 18% of the two ingredients. (That is, picture the three percentages on a number line.)
12% is 4/10 of the way from 8% to 18%. (8 to 18 is a difference of 10; 8 to 12 is a difference of 4; so 12 is 4/10 of the way from 8 to 18.)
That means 4/10 of the mixture needs to be the 18% ingredient; 4/10 of 1000ml is 400ml.
ANSWER: 400ml of the 18% salt solution and 600ml of the 8% salt solution.
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want to obtain a liter of a 12% salt solution, mixing X milliliters of an 8% salt solution with Y milliliters of another 18% salt solution, what will be the number of milliliters in the new solution?
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The answer was already given in the problem description. One Liter must be the amount of volume in the finished solution.
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want to obtain V liters of a T% salt solution, mixing x milliliters of an L% salt solution with y milliliters of another H% salt solution, what will be the number of liters in the new of each solution to use?
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y of the H% material
V-y of the L% material
- , and you can find the other material quantity.
Decide if you want to convert to milliliters of stay in liters.
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