SOLUTION: Tobacco mixture #706 is 10¢ per ounce while mixture #716 is twice that price. How many ounces of the more expensive mixture must be used with 48 ounces of the less expensive mixtu
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Question 1162590: Tobacco mixture #706 is 10¢ per ounce while mixture #716 is twice that price. How many ounces of the more expensive mixture must be used with 48 ounces of the less expensive mixture to make a new mixture that will sell for 76¢ per 5-ounce tin? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Tobacco mixture #706 is 10¢ per ounce while mixture #716 is twice that price.
How many ounces of the more expensive mixture must be used with 48 ounces of the less expensive mixture to make a new mixture that will sell for 76¢ per 5-ounce tin?
:
let x = amt of 20 cent mixture
then
(x+48) = total amt
:
10(48) + 20x = (x + 48)
480 + 20x = 15.2(x + 48)
480 + 20x = 15.2x + 729.6
20x - 15.2x = 729.6 - 480
4.8x = 249.6
x = 52 oz of the 20 cent mixture required
