SOLUTION: You need a 5% alcohol solution. On hand, you have a 35 mL of a 50% alcohol mixture. How much pure water will you need to add to obtain the desired solution? A) Write an equation

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: You need a 5% alcohol solution. On hand, you have a 35 mL of a 50% alcohol mixture. How much pure water will you need to add to obtain the desired solution? A) Write an equation      Log On

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Question 1160428: You need a 5% alcohol solution. On hand, you have a 35 mL of a 50% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
A) Write an equation using the information as it is given above that can be used to solve this problem. Use
x as your variable to represent the amount of pure water you need to use.
Equation:

B) You will need
? mL of pure water
to obtain
? mL of the desired 5% solution.

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
0.5%2A35%2F%28v%2B35%29=0.05
.
.
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This will help but is usually not necessary:
MATERIAL           CONCENTRATION (as fraction)      VOLUME

50% Alcohol                    0.5                   35

Water                          0.0                    v

5% Solution                   0.05                  v+35
   Result

Result wanted is 0.05=%28alcoholquantity%29%2F%28totalvolume%29

0.05=%280.5%2A35%29%2F%28v%2B35%29
This is clear enough. Solve for v.