SOLUTION: how many liters of a 40% alcohol solution must be mixed with 65% solution to obtain 30 L of a 50% alcohol solution

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Question 1157806: how many liters of a 40% alcohol solution must be mixed with 65% solution to obtain 30 L of a 50% alcohol solution
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
L = 40
H = 65
T = 50
M = 30
v, volume of the H %, the 65% alcohol
M-v, volume of the L % alcohol

highlight_green%28Hv%2BL%28M-v%29=MT%29
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Solve for v.
Formula is highlight%28v=M%28%28T-L%29%2F%28H-L%29%29%29