SOLUTION: Ms. Parker mixes a 95% sugar cinnamon-flavored solution with a 90% sugar cherry-flavored solution to make 15 gallons of a new product. The new product is 91% sugar. How much of the

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Ms. Parker mixes a 95% sugar cinnamon-flavored solution with a 90% sugar cherry-flavored solution to make 15 gallons of a new product. The new product is 91% sugar. How much of the      Log On

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Question 1157273: Ms. Parker mixes a 95% sugar cinnamon-flavored solution with a 90% sugar cherry-flavored solution to make 15 gallons of a new product. The new product is 91% sugar. How much of the cherry-flavored solution did she use?
[A] 12 gal [B] 10 gal [C] 3 gal [D] 14 gal
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Another one of these

Want 91%
Available 90% and 95%
The difference from 90 to 95 is in 5 equal parts and you want 4%2F5 of the mix to be from the 90%.

u of the 90%
15-u of the 95%
90u%2B95%2815-u%29=91%2A15
-
90u-95u%2B95%2A15=91%2A15
%2890-95%29u=91%2A15-95%2A15
v=%2815%2891-95%29%2F%2890-95%29%29
highlight%28v=15%284%2F5%29%29-------------------12 liters of the 90% sugar, cherry-flavored solution.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Ms. Parker mixes a 95% sugar cinnamon-flavored solution with a 90% sugar cherry-flavored solution to make 15 gallons of a new product. The new product is 91% sugar. How much of the cherry-flavored solution did she use?
[A] 12 gal [B] 10 gal [C] 3 gal [D] 14 gal
Let amount of cherry-flavored solution be C

Then amount of cinnamon-flavored solution = 15 -C

We then get: .9C + .95(15 - C) = .91(15)

.9C + 14.25 - .95C = 13.65

.9C - .95C = 13.65 - 14.25

 - .05C = - .6

Amount of cherry-flavored solution to mix, or