SOLUTION: How many liters each of a 40% antifreeze solution and a 80% antifreeze solution must be mixed to make 8 liters of a 50% antifreeze solution?
Question 1157175: How many liters each of a 40% antifreeze solution and a 80% antifreeze solution must be mixed to make 8 liters of a 50% antifreeze solution? Answer by VFBundy(438) (Show Source):
You can put this solution on YOUR website! Liters of 40% solution = x
Liters of 80% solution = y
x + y = 8
0.40x + 0.80y = 0.50(8)
x + y = 8
0.40x + 0.80y = 4
Multiply first equation by -0.80:
-0.80 - 0.80y = -6.40
0.40x + 0.80y = 4
Add the equations together:
-0.40x = -2.40
x = 6
Since x = 6, and we know x + y = 8, that means y = 2.
Liters of 40% solution = x = 6
Liters of 80% solution = y = 2
