SOLUTION: Mr. Rosoff works in the lab at a pharmaceutical company. He needs to make 44 liters of a 32% acid solution to test a new product. His supplier only ships a 48% and a 26% solution.

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Question 1156867: Mr. Rosoff works in the lab at a pharmaceutical company. He needs to make 44 liters of a 32% acid solution to test a new product. His supplier only ships a 48% and a 26% solution. Mr. Rosoff decides to make the 32% solution by mixing the 48% solution with the 26% solution. How much of the 48% solution will Mr. Rosoff need to use?
[A] 12 L [B] 44 L [C] 21 L [D] 32 L

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Same idea, different values; see #1156869:
https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1156869.html
https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1156869.html

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This example, he is supplied with 48% and 26% solutions; and he wants to make 44 liters of 32% solution.

Final concentration needs to be 32%, or 0.32 in decimal fraction.
If variable v is for the amount of 48% solution to use, then 44-v is the amount of the 26% solution to use.

To account for the PURE amount of substance in the solutions:
highlight_green%2848v%2B26%2844-v%29=32%2A44%29
Now solve for v.

48v%2B26%2A44-26v=32%2A44
%2848-26%29v%2B26%2A44=32%2A44
%2848-26%29v=32%2A44-26%2A44
highlight_green%28v=44%2832-26%29%2F%2848-26%29%29
v=44%286%2F22%29=highlight_green%2844%283%2F11%29=v%29

highlight%28v=12%29-----------liters of the 48%
-
highlight%2832%29-------------liters of the 26%