SOLUTION: ow many ounces of a 10 % alcohol solution must be mixed with 18 ounces of a 15 % alcohol solution to make a 11 % alcohol​ solution?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: ow many ounces of a 10 % alcohol solution must be mixed with 18 ounces of a 15 % alcohol solution to make a 11 % alcohol​ solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1154789: ow many ounces of a 10 % alcohol solution must be mixed with 18 ounces of a 15 % alcohol solution to make a 11 % alcohol​ solution?
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ounces of 10% alcohol needed
-------------------------------
+%28+.1x+%2B+.15%2A18+%29+%2F+%28+x+%2B+18+%29+=+.11+
+.1x+%2B+2.7+=+.11%2A%28+x+%2B+18+%29+
+.1x+%2B+2.7+=+.11x+%2B+1.98+
+.01x+=+2.7+-+1.98+
+.01x+=+.72+
+x+=+72+
72 ounces of 10% alcohol are needed
-----------------------
check:
+%28+.1x+%2B+.15%2A18+%29+%2F+%28+x+%2B+18+%29+=+.11+
+%28+.1%2A72+%2B+.15%2A18+%29+%2F+%28+x+%2B+18+%29+=+.11+
+%28+7.2+%2B+2.7+%29+%2F+%28+72+%2B+18+%29+=+.11+
+9.9+%2F+90+=+.11+
+1.1+%2F+10+=+.11+
+1.1++=+1.1+
OK

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
ow many ounces of a 10 % alcohol solution must be mixed with 18 ounces of a 15 % alcohol solution to make a 11 % alcohol​ solution?
Let amount of 10% alcohol be T

Then we get: .1T + .15(18) = .11(T + 18)

.1T + .15(18) = .11T + .11(18)

.15(18) - .11(18) = .11T - .1T

.04(18) = .01T