SOLUTION: The manager of a specialty food store combined almonds that cost $6.40 per pound with walnuts that cost $5.90 per pound. How many pounds of each were used to make a 100-pound mixt

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Question 1146450: The manager of a specialty food store combined almonds that cost $6.40 per pound with walnuts that
cost $5.90 per pound. How many pounds of each were used to make a 100-pound mixture that costs
$6.18 per pound?

Found 4 solutions by greenestamps, Glaviolette, MathTherapy, richwmiller:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Standard algebraic solution method....

x pounds at $5.90 per pound, plus (100-x) pounds at $6.40 per pound, equals 100 pounds at $6.18 per pound:

x%285.90%29%2B%28100-x%29%286.40%29+=+100%286.18%29

Straightforward; but some ugly calculations....

A faster method, using only a couple of simple calculations, based on where the $6.18 per pound cost of the mixture lies between $5.90 and $6.40....

(1) On a number line, look at where the 6.18 lies between 5.90 and 6.40. 5.90 to 6.40 is a difference of 0.50; 5.90 to 6.18 is a difference of 0.28. 0.28/0.50 = 28/50 = 56/100.

(2) Therefore 56/100 of the mixture should be the higher priced walnuts.

ANSWER: 56 pounds of the walnuts; 100-56 = 44 pounds of the almonds.

Answer by Glaviolette(140) About Me  (Show Source):
You can put this solution on YOUR website!

Instead of 21 it should be 22 after the =. Therefore, it is 44 after that.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
The manager of a specialty food store combined almonds that cost $6.40 per pound with walnuts that
cost $5.90 per pound. How many pounds of each were used to make a 100-pound mixture that costs
$6.18 per pound?
Correct answer:  


Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Giving the answer with no work is worse than having the wrong answer while showing the work.
One of the main goals on this website is to tutor the students not do their homework for them.