SOLUTION: How many mililiters of a 30 percent solution must be mixed with 12 mililiters of a 5 percent solution to obtain a 20 percent solution

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Question 1145782: How many mililiters of a 30 percent solution must be mixed with 12 mililiters of a 5 percent solution to obtain a 20 percent solution
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How many mililiters of a 30 percent solution must be mixed with 12 mililiters of a 5 percent solution to obtain a 20 percent solution
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Add M mls of 30%
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M*30 + 12*5 = (M + 12)*20

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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How many mililiters x of a H percent solution must be mixed with Y mililiters of a L percent solution to obtain a T percent solution ?
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Unknown volume to use, x of the H% solution

%28Hx%2BLY%29%2F%28x%2BY%29=T
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Hx%2BLY=T%28x%2BY%29

Hx%2BLY=Tx%2BTY
Hx-Tx=TY-LY
%28H-T%29x=Y%28T-L%29
highlight%28x=Y%28%28T-L%29%2F%28H-T%29%29%29--------substitute your given values.