SOLUTION: 3,4,9,7,1,3,4,9,7,1,3... in the sequence above, the numbers 3,4,9,7 and 1 repeat in that order, starting with 3. Whatcis the 43rd term of the sequence? A)6 B)7 C)8 D)9

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Question 1144896: 3,4,9,7,1,3,4,9,7,1,3...
in the sequence above, the numbers 3,4,9,7 and 1 repeat in that order, starting with 3. Whatcis the 43rd term of the sequence?
A)6
B)7
C)8
D)9
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.

You have the sequence 3,4,9,7,1  repeating 8 times, and then 3,4,9 in positions 41,42 and 43.


ANSWER.  9.


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The repeating sequence is 5 numbers. Terms 5, 10, ..., 35, and 40 will all be the last number in the sequence, 1. Then 3 more terms to get to the 43rd term puts you at 9.

ANSWER D

Shortcut: 43/5 = 8 remainder 3, so the 43rd term is the same as the 3rd term: 9