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2 < 3d - 4 < 11 ====>
Add 4 to all three terms. You will get an equivalent inequality
2 + 4 < 3d < 11 + 4
6 < 3d < 15
Divide by 3 both sides. You will get an equivalent inequality
2 < d < 5.
The solutions in integer numbers are d= 3 and d= 4.
They are the only solutions.
ANSWER. There are exactly two integer numbers satisfying given inequality.
