Question 1139010: A,B and C can do a job in 4 days . B can do it in 9 days and C can do it in 8 days . How long would it take A to do it himself ?
Found 3 solutions by VFBundy, MathTherapy, ikleyn: Answer by VFBundy(438) (Show Source):
You can put this solution on YOUR website! A, B, and C, working together, can do 1/4 of the job per day.
A, working alone, can do 1/A of the job per day. (We are trying to figure out what A is.)
B, working alone, can do 1/9 of the job per day.
C, working alone, can do 1/8 of the job per day.
"A, B, and C, working together, can do 1/4 of the job per day.":
1/A + 1/9 + 1/8 = 1/4
Common denominator for left side of equation is: (A)(9)(8) = 72A
Set up the equation using 72A as common denominator on left side of equation, then simplify:
(1*9*8)/72A + (1*8*A)/72A + (1*9*A)/72A = 1/4
72/72A + 8A/72A + 9A/72A = 1/4
(72 + 8A + 9A)/72A = 1/4
(72 + 17A)/72A = 1/4
Cross-multiply:
4(72 + 17A) = 1(72A)
Simplify:
288 + 68A = 72A
288 = 4A
A = 72
It will take A 72 days to do the job himself.
Answer by MathTherapy(10552) (Show Source): Answer by ikleyn(52782) (Show Source):
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