SOLUTION: How many ounces of a gold alloy that costs $460 per ounce must be mixed with 25 ounces of a gold alloy that costs $220 per ounce to make a mixture that costs $310 per ounce?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many ounces of a gold alloy that costs $460 per ounce must be mixed with 25 ounces of a gold alloy that costs $220 per ounce to make a mixture that costs $310 per ounce?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1138415: How many ounces of a gold alloy that costs $460 per
ounce must be mixed with 25 ounces of a gold alloy that costs
$220 per ounce to make a mixture that costs $310 per ounce?

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
H=460 $/ounce
L=220 $/ounce
U = 25 ounces
v = unknown ounces of H priced gold
T=310 $/ounce target

LU%2BHv=T%28v%2BU%29
-
LU%2BHv=Tv%2BTU
Hv-Tv=TU-LU
v%28H-T%29=TU-LU
highlight%28v=%28TU-LU%29%2F%28H-T%29%29
Substitute the given values and evaluate v.