SOLUTION: Word Problems A man is twice as old as his son. His son is twice as old as his sister. The sum of their ages is 77 years. Find each persons age.

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Question 1135247: Word Problems
A man is twice as old as his son. His son is twice as old as his sister. The sum of their ages is 77 years. Find each persons age.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52787) About Me  (Show Source):
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.
Sister + Son      + Man          = 77


Sister + 2*Sister + 2*(2*Sister) = 77


Sister + 2Sister  + 4*Sister     = 77


7*Sister = 77   =================>  Sister = 77/7 = 11.


Answer.  Sister = 11;  Son = 2*11 = 22;  Man = 4*11 = 44.

Solved.


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
PERSON           AGE
man              4x
son              2x
daughter          x
Sum              77

4x%2B2x%2Bx=77
-
7x=77
x=11
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PERSON           AGE
man              44
son              22
daughter         11 
Sum              77