SOLUTION: How many ounces of a 5 % alcohol solution must be mixed with 18 ounces of a 10 % alcohol solution to make a 6 % alcohol​ solution?

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Question 1128477: How many ounces of a 5 % alcohol solution must be mixed with 18 ounces of a 10 % alcohol solution to make a 6 % alcohol​ solution?
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ounces of 5% solution needed
+.1%2A18+=+1.8+ ounces of alcohol in 10% solution
+%28+.05x+%2B+1.8+%29+%2F+%28+x+%2B+18+%29+=+.06+
+.05x+%2B+1.8+=+.06%2A%28+x+%2B+18+%29+
+.05x+%2B+1.8+=+.06x+%2B+1.08+
+.01x+=+.72+
+x+=+72+
72 ounces of 5% solution are needed
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check:
+%28+.05%2A72+%2B+1.8+%29+%2F+%28+72+%2B+18+%29+=+.06+
+%28+3.6+%2B+1.8+%29+%2F+90+=+.06+
+5.4+=+5.4+
OK

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How many ounces of a 5 % alcohol solution must be mixed with 18 ounces of a 10 % alcohol solution to make a 6 % alcohol​ solution?
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Equation:
alch + alch = alch
0.05x + 0.10*18 = 0.06(x+18)
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5x + 180 = 6x + 108
x = 72 (amt. of 5% solution needed)
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Cheers,
Stan H.
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