Question 1128476: Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original price of $ 14.50 each, but later decreased the price of each by $4.00. If they sold all 91 pieces and took in $ 1 comma 039.50, find how many they sold at the original price and how many they sold at the reduced price.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original price of $ 14.50 each, but later decreased the price of each by $4.00. If they sold all 91 pieces and took in $ 1 comma 039.50, find how many they sold at the original price and how many they sold at the reduced price.
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Equations::
Quantity:: original + reduced = 91 pieces
Value::::: 14.5*o + 4*r = 1,039.50
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Modify to solve for "o"
4*o + 4*r = 4*91
14.5*o + 4*r = 1039.5
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Subtract and solve for "o"::
10.5*o = 675.5
o = 64 1/3 (# of pieces sold at the original price)
This cannot be the correct answer because it is not a whole number.
Please check the accuracy of your posted numbers.
Cheers,
Stan H.
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