SOLUTION: Five gallons of a 20% alcohol solution is added to 3 gallons of 30% solution. Two gallons of pure alcohol is added to the resulting solution. What shall be its percentage of concen

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Five gallons of a 20% alcohol solution is added to 3 gallons of 30% solution. Two gallons of pure alcohol is added to the resulting solution. What shall be its percentage of concen      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1127812: Five gallons of a 20% alcohol solution is added to 3 gallons of 30% solution. Two gallons of pure alcohol is added to the resulting solution. What shall be its percentage of concentration of the final solution?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
%280.2%2A5%2B0.3%2A3%29%2F8=%281%2B0.9%29%2F8

1.9%2F8 fraction as alcohol, the 8 gallon part


-

%28%281.9%2F8%29%2A8%2B2%29%2F10

%281.9%2B2%29%2F10

3.9%2F10

39%2F100---------39% alcohol, the resulting 10 gallons

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


(total amount of alcohol) divided by (total amount of solution), converted to a percent.

The amount of alcohol is 20% of the 5 gallons, plus 30% of the 3 gallons, plus 100% of the 2 gallons. The amount of solution is 5 gallons plus 3 gallons plus 2 gallons.

%28%28.20%29%285%29%2B.30%283%29%2B1%282%29%29%2F%285%2B3%2B2%29+=+3.9%2F10+=+39%2F100 = 39%