Question 1127025: A nursery sells KB seed for $5.75/lbs and TF seed for $4.50/lbs. The nursery sells a mixture of the two kinds of seed for $5.25/lbs. Let K represent the amount of KB seed the nursery uses in 5 pounds of the mixture.
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39617)   (Show Source):
Answer by ikleyn(52781)  (Show Source):
You can put this solution on YOUR website! .
When you post to the forum without placing your question, you work against yourself.
Such posts are the subject of ignoring according to the rules of this forum.
What @josgarithmetic does in such cases, is simply violation of the rules of this forum.
So, nobody is responsible for correctness of his (of such) answers,
and you should know that @josgarithmetic produces wrong solutions and wrong answers in half of cases.
I sincerely advise you to correct your behavior in this forum and do not submit posts without questions.
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Oh, brother!!!!
It is NOT "against the rules of this forum" to respond to a message if it is clear what the question is.
The other tutor's response is appropriate, and correct.
Here is a way that will get you to the answer to a question like this much faster and with much less work than the standard algebraic method used by the other tutor.
(1) The $5.25 cost per pound is 3/5 of the way from the $4.50 per pound cost of the TF seed to the $5.75 per pound cost of the KB seed.
(Do some simple arithmetic: 5.25 - 4.50 = .75; 5.75-4.50 = 1.25; .75/1.25 = 3/5)
(2) That means 3/5 of the mixture needs to be the higher priced KB seed.
Therefore, to make 5 pounds of the mixture, you need 3 pounds of the KB seed and 2 pounds of the TF seed.
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