Question 1124591: If you have 1.75L of an 18% alcohol solution, how much pure water must you add in order to decrease the concentration to 5%? Answer by ikleyn(52776) (Show Source):
The amount of the pure alcohol in 1.75 L of the 18% solution is 0.18*1.75 liters = 0.315 liters.
This volume of the pure alcohol will not change and will remain the same after adding water.
So, you need to add, let say, x liter of water to get
= 0.05 (which is 5% of concentration of the final mixture)
So, you need solve this equation.
For it, multiply the both sides of the equation by (0.315+x) to get
0.315 = 0.05*(0.315 + x).
Simplify and solve for x:
0.315 = 0.05*0.315 + 0.05x
0.315 - 0.05*0.315 = 0.05x
x = = 5.985.
Answer. You need to add 5.985 liters of water.
Check. = 0.05. ! Correct !
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