Question 1123843: what quantity of pure acid must be added to 300mL of a 50% acid solution to produce a 60% acid solution? Answer by ikleyn(52777) (Show Source):
Let x be the quantity under the question.
Then your equation is
0.5*300 + x = 0.6*(x+300)
stating that the pure acid amount is the same in ingredients and in the mixture.
x = = 75 mL.
Check. 0.5*300 + 75 = 225 mL of the pure acid.
0.6*(300+75) = 225 mL of the pure acid. ! Correct !
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