Question 1123627: How man liters of 60% alcohol solution must be added to 20 liters of 10% alcohol solution to produce 40% alcohol solution. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How man liters of 60% alcohol solution must be added to 20 liters of 10% alcohol solution to produce 40% alcohol solution.
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s = amount of 60%
t = amount of 10%
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s*60 + 20*10 = (s+20)*40
