SOLUTION: the product of three consecutive positive integers is eight times their sum.what is the sum of their squares

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Question 1117829: the product of three consecutive positive integers is eight times their sum.what is the sum of their squares
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
POSITIVE integers, n-1, n, n+1


%28n-1%29%28n%2B1%29n=8%28n-1%2Bn%2Bn%2B1%29
-
n%28n%5E2-1%29=8%283n%29
n%5E3-n=24n
n%5E3-25n=0
n%28n%5E2-25%29=0

n=0 will not work according to the description.
highlight_green%28n=5%29

Sum Of Their Squares:
4%5E2%2B5%5E2%2B6%5E2
16%2B25%2B36
highlight%2877%29