SOLUTION: A chemist wishes to mix a solution that is 12% acid. She has on hand 10 liters of a 2% acid solution and wishes to add some 16% acid solution to obtain the desired 12% acid solutio
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Question 1117049: A chemist wishes to mix a solution that is 12% acid. She has on hand 10 liters of a 2% acid solution and wishes to add some 16% acid solution to obtain the desired 12% acid solution. How much 16% acid solution should she add? Answer by ikleyn(52794) (Show Source):
pure acid amount + pure acid amount = total pure acid amount
0.02*10 + 0.16*x = 0.12*(10+x) <<<---=== it is your balance equation; x is the amount (in liters) of the 16% solution.
0.02*10 + 0.16x = 0.12*10 + 0.12*x
0.16*x - 0.12*x = 0.12*10 - 0.02*10
(0.16 - 0.12)*x = 0.12*10 - 0.02*10
x = = 25.
Answer. 25 liters of the 16% solution should be added.
Check. = 0.12 = 12% of concentration of the final mixture. ! Correct !
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