Question 1115418: How many six-digit numbers divisible by 20 can be formed from the digits 0, 1, 2, 3, 4, 5 (with repetition).
Found 3 solutions by greenestamps, ikleyn, MathTherapy:
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
The units digit has to be 0 (1 choice -- 0).
The tens digit has to be even (3 choices -- 0, 2, or 4).
Each of the other four digits can be any one of the given digits (6 choices each).
Answer: 1*3*6*6*6*6 = 3888
Answer by ikleyn(52784)  (Show Source):
You can put this solution on YOUR website! .
The units digit has to be 0 (1 choice -- 0).
The tens digit has to be even (3 choices -- 0, 2, or 4).
First digits can be any of five digits (except of zero) (5 choices).
Each of the other three digits can be any one of the given digits (6 choices each).
Answer: 1*3*5*6*6*6 = 3240 six-digits divisible by 20 integer positive numbers can be formed.
Solved.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
How many six-digit numbers divisible by 20 can be formed from the digits 0, 1, 2, 3, 4, 5 (with repetition).
The answer is NOT 3,888, so IGNORE that answer. It's actually 3,240.
|
|
|
