SOLUTION: a 20% dye solution is to be mixed with 59% solution to get 260 l of a 50% solution how many liters of a 20% and 59% solutions will be needed

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: a 20% dye solution is to be mixed with 59% solution to get 260 l of a 50% solution how many liters of a 20% and 59% solutions will be needed      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1113714: a 20% dye solution is to be mixed with 59% solution to get 260 l of a 50% solution how many liters of a 20% and 59% solutions will be needed
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
20%? 59%?
What kind of dye? What kind of solvent?
Not "solution", but maybe DISPERSION!

Use "L" for liters; not "l".


x of the 20%
260-x of the 59%

20x%2B59%28260-x%29=50%2A260
Solve this for x.

If the algebra done carefully, find highlight%28x=60%29 for the 20% dispersion, and therefore highlight%28200%29 for the 59% dispersion dye.