SOLUTION: how many liter of a 20% alcohol solution should be added to a 450 L solution which contain 35% alcohol so that the resulting mixture will be 30% alcohol.
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Question 1110474: how many liter of a 20% alcohol solution should be added to a 450 L solution which contain 35% alcohol so that the resulting mixture will be 30% alcohol. Found 3 solutions by stanbon, josgarithmetic, ikleyn:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how many liters of a 20% alcohol solution should be added to a 450 L solution which contain 35% alcohol so that the resulting mixture will be 30% alcohol.
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Equation::
alch + alch = alch
0.2x + 0.35*450 = 0.3(x+450)
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20x + 35*450 = 30x + 30*450
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10x = 5*450
x = 225 L (amt. of 20% solution needed)
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Cheers,
Stan H.
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The equation for the unknown volume "x" is this
(0.35*450 + 0.2*x) = 0.3*(450+x)
It says: pure alcohol amount in the mixture is the sum of the alcohol amounts in the components.
0.35*450 + 0.2*x = 0.3*450 + 0.3*x
0.35*450 - 0.3*450 = 0.3x - 0.2x
0.05*450 = 0.1x ====> x = = 225.
Answer. 225 liters of the 20% alcohol solution should be added.
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