SOLUTION: if solution a contains 60% calcuim and solution b contains 30% calcium.how much of each solution should be mixed in order to create 100 cups of a solution that contains 36% calcuim

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: if solution a contains 60% calcuim and solution b contains 30% calcium.how much of each solution should be mixed in order to create 100 cups of a solution that contains 36% calcuim      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1106907: if solution a contains 60% calcuim and solution b contains 30% calcium.how much of each solution should be mixed in order to create 100 cups of a solution that contains 36% calcuim
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
60% calcium solution? In what? As melted in something? Not a salt in water; right?

-

-----------------------------------------------------------------------------
if cross%28solution%29 DRY MIXTURE a contains 60% calcuim and cross%28solution%29 DRY MIXTURE b contains 30% calcium.how much of each cross%28solution%29 should be mixed in order to create 100 cups of a cross%28solution%29 that contains 36% calcuim
-----------------------------------------------------------------------------

That now begins to make some sense. The 100 "cups" of mixture is being measured in some container and would be marked in volume measurements. Still faulty unless the concentration is as v/v.

x of the 60%
100-x of the 30%

60x%2B30%28100-x%29=36%2A100
-
6x%2B3%28100-x%29=360
6x%2B300-3x=360
3x=60
x=20
-
100-x=80
-
20 cups of the 60% calcium material
and
80 cups of the 30% calcium material