SOLUTION: two workers take 12 days to paint a house. they work at different speeds. the first worker could paint the house on his own in 18days. how long would it take the second worker to p
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Question 1105736: two workers take 12 days to paint a house. they work at different speeds. the first worker could paint the house on his own in 18days. how long would it take the second worker to paint the house on his own? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! two workers take 12 days to paint a house.
they work at different speeds.
the first worker could paint the house on his own in 18days.
how long would it take the second worker to paint the house on his own?
:
let t = time required by the 2nd worker alone to do the job
let the completed job = 1
Each worker will do a fraction of the job. The two fractions add up to 1 + = 1
multiply equation by 18t, cancel the denominators
12t + 18(12) = 18t
12t + 216 = 18t
216 = 18t - 12t
216 = 6t
t = 216/6
t = 36 days required by the 2nd worker to paint the house
:
:
Check + = 1
reduce fractions + = 1
