SOLUTION: to make a 10% acid solution for chemistry class, Xavier wants to mix some 5% solution with 10L of 20% solution. How many liters of 5% solution should he use?
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Question 1100729: to make a 10% acid solution for chemistry class, Xavier wants to mix some 5% solution with 10L of 20% solution. How many liters of 5% solution should he use? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
Let X = "How many liters of 5% solution should he use".
Your basic equation is THIS:
= 0.1
The numerator is the amount of the pure acid in the mixture, in liters.
The denominator is the total liquid volume, in liters
So, the ratio on the left side of the equation is the concentration of the acid in the mixture.
This concentration must be 10%, which is 0.1, so the equation is.
To solve the equation, multiply both sides by (X+10). You will get
0.05*X + 2 = 0.1*(X+10),
0.05X + 2 = 0.1X + 1 ====> 2 - 1 = 0.1X - 0.05X ====> 1 = 0.05X ====> X = = 20.
Answer. Xavier must use 20 liters of the 5% acid solution.
Check. = 0.01, the correct concentration.
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