SOLUTION: A chemist has a 1% solution of alcohol to mix with a 56% solution to get 110L of a final mixture that is 26% alcohol. How much of each of the original solutions should he use?

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Question 1095549: A chemist has a 1% solution of alcohol to mix with a 56% solution to get 110L of a final mixture that is 26% alcohol. How much of each of the original solutions should he use?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x%2B56%28110-x%29=26%2A110, x for how much of the 1% alcohol
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x%2B56%2A110-56x=26%2A110
-55x=26%2A110-56%2A110
55x=%2856-26%29%2A110
x=2%2856-26%29
highlight%28x=60%29----------Liters of the 1% alcohol.
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highlight%2850%29-----------Liters of the 56% alcohol