SOLUTION: a solution containing 8% salt is to be mixed with a solution containing 16% salt to obtain a 50 liter mixture with 10%. How many liters of each solution should be used?
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Question 1093174: a solution containing 8% salt is to be mixed with a solution containing 16% salt to obtain a 50 liter mixture with 10%. How many liters of each solution should be used? Answer by ikleyn(52788) (Show Source):
let x = volume in liters of the 8% solution,
y = volume of the 16% solution.
Then
x + y = 50, (1) (total volume equation)
0.08x + 0.16y = 0.1*50. (2) (salt content equation)
Express x = 50-y from eq(1), and substitute it into eq(2). You will get
0.08*(50-y) + 0.16y = 5,
4 - 0.08y + 0.16y = 5,
0.08y = 5 - 4 = 1 ====> y = = 12.5.
Answer. 12.5 liters of the 16% solution and 50-12.5 = 37.5 liters of the 8% solution must be mixed.
Check. = 0.1. ! Correct !
