SOLUTION: A mixture contains 24 quarts of water and acid solution, of which 60% is acid. How much of this solution should be drained and replaced with water for the solution to be 40% acid?
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Question 1091692: A mixture contains 24 quarts of water and acid solution, of which 60% is acid. How much of this solution should be drained and replaced with water for the solution to be 40% acid?
Let V be the volume of the mixture to be drained and replaced with water.
Then the pure mixture contents in the final solution is 0.6*24 - 0.6*V quarts,
while the total volume after replacement remains the same, 24 quarts.
So your concentration equation is
= 0.4.
To solve it, multiply both sides by 24:
0.6*24 - 0.6*V = 0.4*24, ====>
0.6*V = 0.6*24 - 0.4*24 = 0.2*24 ====> V = = = 2*4 = 8.
Answer. 8 quarts of the mixture must be drained and replaced.
