SOLUTION: One hundred liters of a 50% solution of a chemical mixture is obtained by mixing a 60% solution with a 20% solution. Using a system of linear equations determine how many liters of
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: One hundred liters of a 50% solution of a chemical mixture is obtained by mixing a 60% solution with a 20% solution. Using a system of linear equations determine how many liters of
Log On
Question 1091275: One hundred liters of a 50% solution of a chemical mixture is obtained by mixing a 60% solution with a 20% solution. Using a system of linear equations determine how many liters of each solution are required to obtain the 50% mixture. Solve the system using matrices. Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
Let x be the volume of the 20% solution,
y be the volume of the 60% solution.
Your system of equations is
x + y = 100, (1) (account for the volume)
0.2x + 0.6*y = 0.5*100 (2) (account for the pure solvent volume)
You can rewrite it equivalently in the form
x + y = 100, (1') (account for the volume)
0.2x + 0.6*y = 50. (2') (account for the pure solvent volume)
The system (1'),(2') is the standard form of equations for the mixture word problems.
You can solve it by applying any appropriate method.
(