SOLUTION: How much of an alloy that is 10% copper should be mixed with 200 ounces of an alloy that is 90% copper in order to get an alloy that is 30% ​copper?

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Question 1091143: How much of an alloy that is 10% copper should be mixed with 200 ounces of an alloy that is 90% copper in order to get an alloy that is 30% ​copper?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
x, how much 10% alloy

%28200%2A90%2B10x%29%2F%28x%2B200%29=30

Solve the equation. It gives what you want. You need to know how to form the equation.

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Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
x, how much 10% alloy

Your governing equation is

%28200%2A90%2B10x%29%2F%28x%2B200%29 = 30


There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


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The equation by @josgarithmetic was incorrect //until he fixed it after my notice.