SOLUTION: Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?

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Question 1084940: Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?
Found 3 solutions by josgarithmetic, ikleyn, adamhen894:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
One tap would fill 1%2F5 tank in 20 minutes. Space of 3%2F5 tank still needs to be filled with this one remaining tap.


%28%281%2F5%29%2F20%29%2At=3%2F5, find t, time needed.

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
If "two identical taps fill 2/5 of a tank in 20 minutes", it means that one tap fills 1/5 of the tank volume in 20 minutes.


So, it will take 3 times 20 minutes to fill the rest 3%2F5 of the tank volume if only one tap works to fill this 3%2F5 part of the tank volume.


Answer. The time required which is under the question is 1 hour.


Answer by adamhen894(15) About Me  (Show Source):
You can put this solution on YOUR website!
two identical tap fill 2/5 of a tank in 20 mins, which means,
one tap fill 1/5 of a tank in 20 mins
and there is still 3/5 of a tank waiting to be filled,
so it takes three times 20 mins to fill the remaining tank.
3 * 20 = 60 mins
i would love to hear more alternative ways to solve the problems.
adamchen894@gmail.com