SOLUTION: A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
55%
salt and Solution B is
80%
salt. She wa
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-> SOLUTION: A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
55%
salt and Solution B is
80%
salt. She wa
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Question 1083671: A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
55%
salt and Solution B is
80%
salt. She wants to obtain
160
ounces of a mixture that is
60%
salt. How many ounces of each solution should she use?
You can put this solution on YOUR website! solutionA
x ounces of 55%salt
solutionB
(160-x)ounces of 80% salt
mixture of two solution
160 ounces of 60% salt
now we can set up the equation, solve for x
0.55x+0.8(160-x)=0.6*160
x= 128 ounces of 55% salt
and 32 ounces of 60% salt
input x value into equation, they equal to each other.
if you have alternative way of solving it, i would love to hear
adamchen894@gmail.com
You can put this solution on YOUR website! A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
55% salt and Solution B is 80% salt.
She wants to obtain 160 ounces of a mixture that is
60% salt. How many ounces of each solution should she use?
==============
Ignoring the fact that 80% salt and 55% salt is not possible:
---
e = amount of 80%
f = amount of 55%
---
e + f = 160 (total solution)
80e + 55f = 60*160 (total salt)
-----
16e + 11f = 1920
f = 160 - e
16e + 11*(160-e) = 1920
16e + 1760 - 11e = 1920
5e = 160
e = 32 ounces
f = 128 ounces
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