SOLUTION: A chemist needs a 30% acid solution. How much pure acid needs to be mixed with 5 milliliter a of a 10% acid solution to obtain the desired solution?

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Question 1080562: A chemist needs a 30% acid solution. How much pure acid needs to be mixed with 5 milliliter a of a 10% acid solution to obtain the desired solution?
Found 2 solutions by Fombitz, rapture:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let X be the amount of pure acid,
5%2810%29%2BX%28100%29=%285%2BX%29%2830%29
5%2B10X=%285%2BX%293
5%2B10X=15%2B3X
7X=10
Solve for X.

Answer by rapture(86) About Me  (Show Source):
You can put this solution on YOUR website!
What you want, where x is the amount of pure acid added in mL:
0.10(5) + x = 0.50(x + 5)
Solve for x to find your answer.